以压电体(K0.45Na0.55)0.98 Li0.02 Nb0.77 Ta0.18Sb.05 O3和压磁体Co0.85 Cu0.15 Fe2O为原料,通过传统的固相反应法制备了(1-x) [(K0.45 Na0.55)0.98Li0.02Nb0.77Ta0.18Sb0.05 O3]-xCo0.85Cu0.15 Fe2 O4多铁性复合陶瓷,并使用X射线衍射仪、扫描电子显微镜、压电测试仪、铁电测试仪和磁电耦合测试仪对物相、显微结构、压电、铁电、磁电耦合性能进行了分析.结果表明,复合陶瓷的相结构保持为(K45 Na0.55)n98Li0.02Nb0.77Ta0.18Sb0.05O3和Co0.85Cu0.15 Fe2O4两种物相,但两者之间发生了轻微的化学反应.随着Co0.85Cu0.15 Fe2 O4压磁相含量的增加,复合陶瓷的压电系数从56 pC/N减小到21 pC/N,剩余极化强度略有降低.在压磁相含量为0.2时可获得4.3 mV·cm-1·Oe-1的最佳磁电耦合系数.
参考文献
[1] | Eerenstein W;Mathur ND;Scott JF.Multiferroic and magnetoelectric materials[J].Nature,20067104(7104):759-765. |
[2] | Su WN;Wang DH;Cao QQ;Han ZD;Yin J;Zhang JR;Du YW.Large polarization and enhanced magnetic properties in BiFeO3 ceramic prepared by high-pressure synthesis[J].Applied physics letters,20079(9):92905-1-92905-3-0. |
[3] | 孙慧;王浩;孟德欢;毛翔宇;陈小兵.Bi5FeTi3O15薄膜室温多铁性及其磁性机理[J].硅酸盐学报,2013(3):392-395. |
[4] | Yong Gao;Jialiang Zhang;Yalin Qing.Remarkably Strong Piezoelectricity of Lead-Free (K_(0.45)Na_(0.55))_(0.98)Li_(0.02)(Nb_(0.77)Ta_(0.18)Sb_(0.05))O_3 Ceramic[J].Journal of the American Ceramic Society,20119(9):2968-2973. |
[5] | Manoj Kumar;K.L. Yadav.Synthesis of nanocrystalline xCuFe_2O_4-(1-x)BiFeO_3 magnetoelectric composite by chemical method[J].Materials Letters,200710(10):2089-2092. |
[6] | 袁昌来*;周秀娟;轩敏杰;许积文;杨云;刘心宇.K0.5Na0.5NbO3-LiSbO3-BiFeO3/CuFe2O4复合陶瓷的制备与磁电性能研究[J].物理学报,2013(4):452-456. |
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