以(NH4)2S3O8为氧化剂、十二烷基苯磺酸(DBSA)为乳化剂和掺杂剂、苯胺(An)为单体,原位乳液聚合制备了聚苯胺(PAn)/聚甲基丙烯酸甲酯(PAMM)导电复合材料.观察了复合物粒子形貌.研究了反应温度、反应时间、掺杂酸及单体用量等对聚苯胺产率、导电性能的影响.结果表明:复合物粒子为纳米级核/壳结构.适宜的掺杂条件为:APS/An(摩尔比)=1.0~1.2;DBSA/An(摩尔比)=1.5~1.8;An/PMMA(质量比)=1∶4;反应时间18小时;反应温度低于5℃.红外光谱研究表明:PMMA的加入会使体系的掺杂率有所降低.
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