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研究了2种不同Ti/Zr比例的Ti/Zr-V-Mn-Ni-Cr系多元AB2型贮氢电极合金A(Ti0.7Zr0.3V0.2Mn0.4Ni0.9Cr0.5)和B(Ti0.5Zr0.5V0.2Mn0.4Ni0.9Cr0.5)的电化学放电容量与合金相结构关系.2种合金的电化学循环稳定性都很好,但是合金A的放电容量明显高于合金B.2种合金均由C14 Laves相和TiNi相构成,A的主要组成相是TiNi,而B的主要组成相是C14 Laves.合金的贮氢量主要取决于TiNi相的含量,由于TiNi相的贮氢容量较低,所以该合金的贮氢容量也很低,并且由于合金B中TiNi相的含量低于合金A,所以B的放电容量也低于A.

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