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在140℃的条件下,用KMnO4分别与甲醇、乙醇、丙醇、丁醇、乙二醇、1,3-丙二醇以及1,4-丁二醇进行水热反应24h.采用X射线粉末衍射(XRD)与环境扫描电子显微镜(SEM)对反应产物进行表征.结果表明,KMnO4与乙醇、丙醇、丁醇以及1,4-丁二醇反应均可以得到较纯的棒状MnOOH晶体.KMnO4与甲醇、1,3-丙二醇反应不仅得到了MnOOH晶体并且也得到Mn3O4晶体,而与乙二醇的反应只得到了Mn3O4晶体.并简单探讨了形成这种规律的原因.

参考文献

[1] Bach S;Henry M;Baffier N et al.Sol-gel Synthesis of Manganese Oxides[J].Journal of Solid State Chemistry,1990,88(02):325-329.
[2] Bach S;Pereira-Ramos J P;Baffier N et al.Birnessite Manganese Dioxide Synthesized Via a Sol-gel Process:a New Rechargeable Catholic Material for Lithium Batteries[J].Electrochimica Acta,1991,36(10):1595-1599.
[3] Matsukik;Kamadah .Oxygen Reduction Electrocatalysis on Some Manganese Oxides[J].Electrochimica Acta,1986,31(01):13-18.
[4] 王辉,袁中直,关菊英,王莉.方形γ-MnOOH的制备及其电催化氧还原的性能[J].电源技术,2008(05):323-325.
[5] Wenzhong Wang;Congkang Xu;Guanghou Wang;Yingkai Liu;Changlin Zheng .Preparation of Smooth Single-Crystal Mn_3O_4 Nanowires[J].Advanced Materials,2002(11):837-840.
[6] Ramesh C;Hirofumi K;Yoshitaka M et al.Recovery of Lithium from Seawater Using Manganese Oxide Adsorbent (H1.6Mn1.6O4) Derived from Li1.6Mn1.5O4[J].Industrial and Engineering Chemistry Research,2001,40(09):2054-2058.
[7] 仲维卓.水热条件下纳米晶的形成机理[J].人工晶体学报,1997(03):194.
[8] Gao, T;Krumeich, F;Nesper, R;Fjellvag, H;Norby, P .Microstructures, Surface Properties, and Topotactic Transitions of Manganite Nanorods[J].Inorganic Chemistry: A Research Journal that Includes Bioinorganic, Catalytic, Organometallic, Solid-State, and Synthetic Chemistry and Reaction Dynamics,2009(13):6242-6250.
[9] Zhang YG;Liu Y;Guo F;Hu YH;Liu XZ;Qian YT .Single-crystal growth of MnOOH and beta-MnO2 microrods at lower temperatures[J].Solid State Communications,2005(8):523-527.
[10] 乔涛,邢蓉,张永才,胡效亚.γ-MnOOH和β-MnO2纳米线的低温合成与表征[J].功能材料,2004(z1):2823-2826.
[11] Zheng DS;Yin ZL;Zhang WM;Tan XJ;Sun SX .Novel branched gamma-MnOOH and beta-MnO2 multipod nanostructures[J].Crystal growth & design,2006(8):1733-1735.
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