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以五氧化二钒和过氧化氢为原料,采用溶胶-凝胶法合成片状V2O5,再采用化学氧化法,通过改变氧化剂的加入顺序,制备出了不同结构的五氧化二钒/聚吡咯(V2O5/PPy)复合材料.运用X射线粉末衍射(XRD)、扫描电子显微镜(SEM)和比表面积(BET)表征了材料的结构和形貌,用四探针测试了材料的电导率.结果表明,氧化剂的加入方式不同,所得复合材料结构和形貌明显不同.先加氧化剂时,吡咯在V2O5的层间聚合,XRD测试表明所得复合材料的主要衍射峰对应的层间距由0.40806 nm(V2O5)增大到0.41019 nm;而先加入吡咯单体时,吡咯在V2O5的表面吸附聚合,复合材料的层间距没有明显变化.先加入氧化剂所得复合材料具有最高的放电比容量(271.8 mAh/g),并且循环50次后,仍有225.4 mAh/g的放电比容量.

参考文献

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